3/7a+19=10

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Solution for 3/7a+19=10 equation: 



3/7a+19=10

We move all terms to the left:

3/7a+19-(10)=0



Domain of the equation: 7a!=0

a!=0/7

a!=0

a∈R



We add all the numbers together, and all the variables

3/7a+9=0

We multiply all the terms by the denominator


9*7a+3=0

Wy multiply elements

63a+3=0

We move all terms containing a to the left, all other terms to the right

63a=-3

a=-3/63

a=-1/21

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