3/7k+11=16

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Solution for 3/7k+11=16 equation: 



3/7k+11=16

We move all terms to the left:

3/7k+11-(16)=0



Domain of the equation: 7k!=0

k!=0/7

k!=0

k∈R



We add all the numbers together, and all the variables

3/7k-5=0

We multiply all the terms by the denominator


-5*7k+3=0

Wy multiply elements

-35k+3=0

We move all terms containing k to the left, all other terms to the right

-35k=-3

k=-3/-35

k=3/35

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