3/7m+8=1/2m+2

Solution for 3/7m+8=1/2m+2 equation:

3/7m+8=1/2m+2

We move all terms to the left:

3/7m+8-(1/2m+2)=0


Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R



Domain of the equation: 2m+2)!=0

m∈R


We get rid of parentheses

3/7m-1/2m-2+8=0

We calculate fractions


6m/14m^2+(-7m)/14m^2-2+8=0

We add all the numbers together, and all the variables

6m/14m^2+(-7m)/14m^2+6=0

We multiply all the terms by the denominator


6m+(-7m)+6*14m^2=0

Wy multiply elements

84m^2+6m+(-7m)=0

We get rid of parentheses

84m^2+6m-7m=0

We add all the numbers together, and all the variables

84m^2-1m=0

a = 84; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·84·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*84}=\frac{0}{168}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*84}=\frac{2}{168}
=1/84
$