3/7m=1+m

Solution for 3/7m=1+m equation:

3/7m=1+m

We move all terms to the left:

3/7m-(1+m)=0


Domain of the equation: 7m!=0

m!=0/7

m!=0

m∈R


We add all the numbers together, and all the variables

3/7m-(m+1)=0

We get rid of parentheses

3/7m-m-1=0

We multiply all the terms by the denominator


-m*7m-1*7m+3=0

Wy multiply elements

-7m^2-7m+3=0

a = -7; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·(-7)·3
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{133}}{2*-7}=\frac{7-\sqrt{133}}{-14}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{133}}{2*-7}=\frac{7+\sqrt{133}}{-14}
$