3/7t+10=2

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Solution for 3/7t+10=2 equation:



3/7t+10=2
We move all terms to the left:
3/7t+10-(2)=0
Domain of the equation: 7t!=0
t!=0/7
t!=0
t∈R
We add all the numbers together, and all the variables
3/7t+8=0
We multiply all the terms by the denominator
8*7t+3=0
Wy multiply elements
56t+3=0
We move all terms containing t to the left, all other terms to the right
56t=-3
t=-3/56
t=-3/56

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