3/7x+35=9/x+5-5/7

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Solution for 3/7x+35=9/x+5-5/7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/7)*x+35 = 9/x-(5/7)+5 // - 9/x-(5/7)+5

(3/7)*x-(9/x)+5/7-5+35 = 0

(3/7)*x-9*x^-1+5/7-5+35 = 0

3/7*x^1-9*x^-1+215/7*x^0 = 0

(3/7*x^2+215/7*x^1-9*x^0)/(x^1) = 0 // * x^2

x^1*(3/7*x^2+215/7*x^1-9*x^0) = 0

x^1

(3/7)*x^2+(215/7)*x-9 = 0

(3/7)*x^2+(215/7)*x-9 = 0

DELTA = (215/7)^2-(-9*4*(3/7))

DELTA = 46981/49

DELTA > 0

x = ((46981/49)^(1/2)-(215/7))/(2*(3/7)) or x = (-(215/7)-(46981/49)^(1/2))/(2*(3/7))

x = 7/6*((46981/49)^(1/2)-215/7) or x = -7/6*((46981/49)^(1/2)+215/7)

x in { -7/6*((46981/49)^(1/2)+215/7), 7/6*((46981/49)^(1/2)-215/7)} 

x in { -7/6*((46981/49)^(1/2)+215/7), 7/6*((46981/49)^(1/2)-215/7) }

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