3/7y+13=19

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Solution for 3/7y+13=19 equation: 



3/7y+13=19

We move all terms to the left:

3/7y+13-(19)=0



Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



We add all the numbers together, and all the variables

3/7y-6=0

We multiply all the terms by the denominator


-6*7y+3=0

Wy multiply elements

-42y+3=0

We move all terms containing y to the left, all other terms to the right

-42y=-3

y=-3/-42

y=1/14

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