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3/7y-9=14y
We move all terms to the left:
3/7y-9-(14y)=0
Domain of the equation: 7y!=0We add all the numbers together, and all the variables
y!=0/7
y!=0
y∈R
-14y+3/7y-9=0
We multiply all the terms by the denominator
-14y*7y-9*7y+3=0
Wy multiply elements
-98y^2-63y+3=0
a = -98; b = -63; c = +3;
Δ = b2-4ac
Δ = -632-4·(-98)·3
Δ = 5145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5145}=\sqrt{49*105}=\sqrt{49}*\sqrt{105}=7\sqrt{105}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-7\sqrt{105}}{2*-98}=\frac{63-7\sqrt{105}}{-196} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+7\sqrt{105}}{2*-98}=\frac{63+7\sqrt{105}}{-196} $
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