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3/8(2x-8)=-3/4x
We move all terms to the left:
3/8(2x-8)-(-3/4x)=0
Domain of the equation: 8(2x-8)!=0
x∈R
Domain of the equation: 4x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
3/8(2x-8)+3/4x=0
We calculate fractions
12x/(64x^2-256x)+(24x2/(64x^2-256x)=0
We calculate terms in parentheses: +(24x2/(64x^2-256x), so:determiningTheFunctionDomain 24x^2+12x/(64x^2-256x)=0
24x2/(64x^2-256x
We multiply all the terms by the denominator
24x2
We add all the numbers together, and all the variables
24x^2
Back to the equation:
+(24x^2)
We multiply all the terms by the denominator
24x^2*(64x^2-256x)+12x=0
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