3/8(48-16x)=4(4+2x)

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Solution for 3/8(48-16x)=4(4+2x) equation: 



3/8(48-16x)=4(4+2x)

We move all terms to the left:

3/8(48-16x)-(4(4+2x))=0



Domain of the equation: 8(48-16x)!=0

x∈R



We add all the numbers together, and all the variables

3/8(-16x+48)-(4(2x+4))=0

We multiply all the terms by the denominator


-((4(2x+4)))*8(-16x+48)+3=0



We calculate terms in parentheses: -((4(2x+4)))*8(-16x+48), so:

(4(2x+4)))*8(-16x+48

We add all the numbers together, and all the variables

-16x+(4(2x+4)))*8(+48

Back to the equation:

-(-16x+(4(2x+4)))*8(+48)



We add all the numbers together, and all the variables

-(-16x+(4(2x+4)))*848+3=0

We move all terms containing x to the left, all other terms to the right

-(-16x+(4(2x+4)))*848=-3

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