3/8(c-4)=1/4(9-c)

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Solution for 3/8(c-4)=1/4(9-c) equation: 



3/8(c-4)=1/4(9-c)

We move all terms to the left:

3/8(c-4)-(1/4(9-c))=0



Domain of the equation: 8(c-4)!=0

c∈R





Domain of the equation: 4(9-c))!=0

c∈R



We add all the numbers together, and all the variables

3/8(c-4)-(1/4(-1c+9))=0

We calculate fractions


(12c(-)/(8(c-4)*4(-1c+9)))+(-8cc/(8(c-4)*4(-1c+9)))=0



We calculate terms in parentheses: +(12c(-)/(8(c-4)*4(-1c+9))), so:

12c(-)/(8(c-4)*4(-1c+9))

We add all the numbers together, and all the variables

12c0/(8(c-4)*4(-1c+9))

We multiply all the terms by the denominator


12c0

We add all the numbers together, and all the variables

12c

Back to the equation:

+(12c)





We calculate terms in parentheses: +(-8cc/(8(c-4)*4(-1c+9))), so:

-8cc/(8(c-4)*4(-1c+9))

We multiply all the terms by the denominator


-8cc

Back to the equation:

+(-8cc)



We get rid of parentheses

12c-8cc=0

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