3/8(p-8)+1/2p=(p-6)

Solution for 3/8(p-8)+1/2p=(p-6) equation:

3/8(p-8)+1/2p=(p-6)

We move all terms to the left:

3/8(p-8)+1/2p-((p-6))=0


Domain of the equation: 8(p-8)!=0

p∈R



Domain of the equation: 2p!=0

p!=0/2

p!=0

p∈R


We calculate fractions


-((p-6))+6p/(16p^2-128p)+(8pp/(16p^2-128p)=0


We calculate terms in parentheses: -((p-6)), so:

(p-6)

We get rid of parentheses

p-6

Back to the equation:

-(p-6)



We calculate terms in parentheses: +(8pp/(16p^2-128p), so:

8pp/(16p^2-128p

We multiply all the terms by the denominator


8pp

Back to the equation:

+(8pp)


We get rid of parentheses

-p+6p/(16p^2-128p)+8pp+6=0

We multiply all the terms by the denominator


-p*(16p^2-128p)+6p+8pp*(16p^2-128p)+6*(16p^2-128p)=0

We add all the numbers together, and all the variables

6p-p*(16p^2-128p)+8pp*(16p^2-128p)+6*(16p^2-128p)=0

We multiply parentheses

-16p^3+128p^2+128p^3-1024p^2+96p^2+6p-768p=0

We do not support eppression: p^3