3/8(y-40)=16

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Solution for 3/8(y-40)=16 equation:



3/8(y-40)=16
We move all terms to the left:
3/8(y-40)-(16)=0
Domain of the equation: 8(y-40)!=0
y∈R
We multiply all the terms by the denominator
-16*8(y-40)+3=0
Wy multiply elements
-128y(y+3=0

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