3/8(y-40)=16

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Solution for 3/8(y-40)=16 equation: 



3/8(y-40)=16

We move all terms to the left:

3/8(y-40)-(16)=0



Domain of the equation: 8(y-40)!=0

y∈R



We multiply all the terms by the denominator


-16*8(y-40)+3=0

Wy multiply elements

-128y(y+3=0

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