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3/8h+4=1/2(h+4)
We move all terms to the left:
3/8h+4-(1/2(h+4))=0
Domain of the equation: 8h!=0
h!=0/8
h!=0
h∈R
Domain of the equation: 2(h+4))!=0We calculate fractions
h∈R
(6hh/(16h^2h+(-(1*8h)/(16h^2h+4=0
We can not solve this equation
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