3/8x+1+8/2x+5=1

Solution for 3/8x+1+8/2x+5=1 equation:

3/8x+1+8/2x+5=1

We move all terms to the left:

3/8x+1+8/2x+5-(1)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

3/8x+8/2x+5=0

We calculate fractions


6x/16x^2+64x/16x^2+5=0

We multiply all the terms by the denominator


6x+64x+5*16x^2=0

We add all the numbers together, and all the variables

70x+5*16x^2=0

Wy multiply elements

80x^2+70x=0

a = 80; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·80·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*80}=\frac{-140}{160}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*80}=\frac{0}{160}
=0
$