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3/8x+1.5x=69
We move all terms to the left:
3/8x+1.5x-(69)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
1.5x+3/8x-69=0
We multiply all the terms by the denominator
(1.5x)*8x-69*8x+3=0
We add all the numbers together, and all the variables
(+1.5x)*8x-69*8x+3=0
We multiply parentheses
8x^2-69*8x+3=0
Wy multiply elements
8x^2-552x+3=0
a = 8; b = -552; c = +3;
Δ = b2-4ac
Δ = -5522-4·8·3
Δ = 304608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304608}=\sqrt{16*19038}=\sqrt{16}*\sqrt{19038}=4\sqrt{19038}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-552)-4\sqrt{19038}}{2*8}=\frac{552-4\sqrt{19038}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-552)+4\sqrt{19038}}{2*8}=\frac{552+4\sqrt{19038}}{16} $
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