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3/8x+15=x
We move all terms to the left:
3/8x+15-(x)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-1x+3/8x+15=0
We multiply all the terms by the denominator
-1x*8x+15*8x+3=0
Wy multiply elements
-8x^2+120x+3=0
a = -8; b = 120; c = +3;
Δ = b2-4ac
Δ = 1202-4·(-8)·3
Δ = 14496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14496}=\sqrt{16*906}=\sqrt{16}*\sqrt{906}=4\sqrt{906}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-4\sqrt{906}}{2*-8}=\frac{-120-4\sqrt{906}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+4\sqrt{906}}{2*-8}=\frac{-120+4\sqrt{906}}{-16} $
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