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3/8x+4=1/2x
We move all terms to the left:
3/8x+4-(1/2x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/8x-(+1/2x)+4=0
We get rid of parentheses
3/8x-1/2x+4=0
We calculate fractions
6x/16x^2+(-8x)/16x^2+4=0
We multiply all the terms by the denominator
6x+(-8x)+4*16x^2=0
Wy multiply elements
64x^2+6x+(-8x)=0
We get rid of parentheses
64x^2+6x-8x=0
We add all the numbers together, and all the variables
64x^2-2x=0
a = 64; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·64·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*64}=\frac{0}{128} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*64}=\frac{4}{128} =1/32 $
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