3/8x+4=1/5x+5=

Solution for 3/8x+4=1/5x+5= equation:

3/8x+4=1/5x+5=

We move all terms to the left:

3/8x+4-(1/5x+5)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 5x+5)!=0

x∈R


We get rid of parentheses

3/8x-1/5x-5+4=0

We calculate fractions


15x/40x^2+(-8x)/40x^2-5+4=0

We add all the numbers together, and all the variables

15x/40x^2+(-8x)/40x^2-1=0

We multiply all the terms by the denominator


15x+(-8x)-1*40x^2=0

Wy multiply elements

-40x^2+15x+(-8x)=0

We get rid of parentheses

-40x^2+15x-8x=0

We add all the numbers together, and all the variables

-40x^2+7x=0

a = -40; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-40)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-40}=\frac{-14}{-80}
=7/40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-40}=\frac{0}{-80}
=0
$