3/8y+3/4y=3

Solution for 3/8y+3/4y=3 equation:

3/8y+3/4y=3

We move all terms to the left:

3/8y+3/4y-(3)=0


Domain of the equation: 8y!=0

y!=0/8

y!=0

y∈R



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We calculate fractions


12y/32y^2+24y/32y^2-3=0

We multiply all the terms by the denominator


12y+24y-3*32y^2=0

We add all the numbers together, and all the variables

36y-3*32y^2=0

Wy multiply elements

-96y^2+36y=0

a = -96; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-96)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-96}=\frac{-72}{-192}
=3/8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-96}=\frac{0}{-192}
=0
$