3/9x+20=80

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Solution for 3/9x+20=80 equation: 



3/9x+20=80

We move all terms to the left:

3/9x+20-(80)=0



Domain of the equation: 9x!=0

x!=0/9

x!=0

x∈R



We add all the numbers together, and all the variables

3/9x-60=0

We multiply all the terms by the denominator


-60*9x+3=0

Wy multiply elements

-540x+3=0

We move all terms containing x to the left, all other terms to the right

-540x=-3

x=-3/-540

x=1/180

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