3/a=(2a+3)/(a+1)-2

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Solution for 3/a=(2a+3)/(a+1)-2 equation: 



3/a=(2a+3)/(a+1)-2

We move all terms to the left:

3/a-((2a+3)/(a+1)-2)=0



Domain of the equation: a!=0

a∈R





Domain of the equation: (a+1)-2)!=0

a∈R



We calculate fractions


(3a+3)/(a^2+a)+(-((2a+3)*a)/(a^2+a)=0



We calculate terms in parentheses: +(-((2a+3)*a)/(a^2+a), so:

-((2a+3)*a)/(a^2+a

We multiply all the terms by the denominator


-((2a+3)*a)



We calculate terms in parentheses: -((2a+3)*a), so:

(2a+3)*a

We multiply parentheses

2a^2+3a

Back to the equation:

-(2a^2+3a)



We get rid of parentheses

-2a^2-3a

Back to the equation:

+(-2a^2-3a)



We get rid of parentheses

-2a^2-3a+(3a+3)/(a^2+a)=0

We multiply all the terms by the denominator


-2a^2*(a^2+a)-3a*(a^2+a)+(3a+3)=0

We multiply parentheses

-2a^2*(a^2+a)-3a^3-3a^2+(3a+3)=0

We get rid of parentheses

-2a^2*(a^2+a)-3a^3-3a^2+3a+3=0

We do not support eapression: a^3

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