3/c-2=3/2c-5

Solution for 3/c-2=3/2c-5 equation:

3/c-2=3/2c-5

We move all terms to the left:

3/c-2-(3/2c-5)=0


Domain of the equation: c!=0

c∈R



Domain of the equation: 2c-5)!=0

c∈R


We get rid of parentheses

3/c-3/2c+5-2=0

We calculate fractions


6c/2c^2+(-3c)/2c^2+5-2=0

We add all the numbers together, and all the variables

6c/2c^2+(-3c)/2c^2+3=0

We multiply all the terms by the denominator


6c+(-3c)+3*2c^2=0

Wy multiply elements

6c^2+6c+(-3c)=0

We get rid of parentheses

6c^2+6c-3c=0

We add all the numbers together, and all the variables

6c^2+3c=0

a = 6; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*6}=\frac{-6}{12}
=-1/2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*6}=\frac{0}{12}
=0
$