3/k+1-k/2=0

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Solution for 3/k+1-k/2=0 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

3/k-(k/2)+1 = 0

3*k^-1-1/2*k^1+1*k^0 = 0

(1*k^1-1/2*k^2+3*k^0)/(k^1) = 0 // * k^2

k^1*(1*k^1-1/2*k^2+3*k^0) = 0

k^1

(-1/2)*k^2+k+3 = 0

(-1/2)*k^2+k+3 = 0

DELTA = 1^2-(3*4*(-1/2))

DELTA = 7

DELTA > 0

k = (7^(1/2)-1)/(2*(-1/2)) or k = (-7^(1/2)-1)/(2*(-1/2))

k = 1-7^(1/2) or k = 7^(1/2)+1

k in { 1-7^(1/2), 7^(1/2)+1} 

k in { 1-7^(1/2), 7^(1/2)+1 }

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