3/m+5/2m=5

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Solution for 3/m+5/2m=5 equation:



3/m+5/2m=5
We move all terms to the left:
3/m+5/2m-(5)=0
Domain of the equation: m!=0
m∈R
Domain of the equation: 2m!=0
m!=0/2
m!=0
m∈R
We calculate fractions
6m/2m^2+5m/2m^2-5=0
We multiply all the terms by the denominator
6m+5m-5*2m^2=0
We add all the numbers together, and all the variables
11m-5*2m^2=0
Wy multiply elements
-10m^2+11m=0
a = -10; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-10)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-10}=\frac{-22}{-20} =1+1/10 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-10}=\frac{0}{-20} =0 $

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