3/m-3=-7/8m+2

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Solution for 3/m-3=-7/8m+2 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

3/m-3 = (-7/8)*m+2 // - (-7/8)*m+2

3/m-((-7/8)*m)-3-2 = 0

(7/8)*m+3/m-3-2 = 0

7/8*m^1+3*m^-1-5*m^0 = 0

(7/8*m^2-5*m^1+3*m^0)/(m^1) = 0 // * m^2

m^1*(7/8*m^2-5*m^1+3*m^0) = 0

m^1

(7/8)*m^2-5*m+3 = 0

(7/8)*m^2-5*m+3 = 0

DELTA = (-5)^2-(3*4*(7/8))

DELTA = 29/2

DELTA > 0

m = ((29/2)^(1/2)+5)/(2*(7/8)) or m = (5-(29/2)^(1/2))/(2*(7/8))

m = 4/7*((29/2)^(1/2)+5) or m = 4/7*(5-(29/2)^(1/2))

m in { 4/7*(5-(29/2)^(1/2)), 4/7*((29/2)^(1/2)+5)} 

m in { 4/7*(5-(29/2)^(1/2)), 4/7*((29/2)^(1/2)+5) }

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