3/n+1=4/n+4

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Solution for 3/n+1=4/n+4 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

3/n+1 = 4/n+4 // - 4/n+4

3/n-(4/n)-4+1 = 0

3/n-4*n^-1-4+1 = 0

-1*n^-1 = 3 // : -1

n^-1 = -3

-1 < 0

1/(n^1) = -3 // * n^1

1 = -3*n^1 // : -3

-1/3 = n^1

n = -1/3

n = -1/3

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