3/n=n/12

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Solution for 3/n=n/12 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

3/n = n/12 // - n/12

3/n-(n/12) = 0

3*n^-1-1/12*n^1 = 0

(3*n^0-1/12*n^2)/(n^1) = 0 // * n^2

n^1*(3*n^0-1/12*n^2) = 0

n^1

(-1/12)*n^2+3 = 0

(-1/12)*n^2+3 = 0

DELTA = 0^2-(3*4*(-1/12))

DELTA = 1

DELTA > 0

n = (1^(1/2)+0)/(2*(-1/12)) or n = (0-1^(1/2))/(2*(-1/12))

n = -6 or n = 6

n in { -6, 6} 

n in { -6, 6 }

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