3/q+4/3)=2

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Solution for 3/q+4/3)=2 equation:



3/q+4/3)=2
We move all terms to the left:
3/q+4/3)-(2)=0
Domain of the equation: q!=0
q∈R
We calculate fractions
()/3q^2+4q/3q^2=0
We multiply all the terms by the denominator
4q+()=0
We add all the numbers together, and all the variables
4q=0
q=0/4
q=0

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