3/q+4/3)=2

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Solution for 3/q+4/3)=2 equation: 



3/q+4/3)=2

We move all terms to the left:

3/q+4/3)-(2)=0



Domain of the equation: q!=0

q∈R



We calculate fractions


()/3q^2+4q/3q^2=0

We multiply all the terms by the denominator


4q+()=0

We add all the numbers together, and all the variables

4q=0

q=0/4

q=0

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