3/q-4=2/5q

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Solution for 3/q-4=2/5q equation:


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

3/q-4 = (2/5)*q // - (2/5)*q

3/q-((2/5)*q)-4 = 0

(-2/5)*q+3/q-4 = 0

3*q^-1-2/5*q^1-4*q^0 = 0

(3*q^0-2/5*q^2-4*q^1)/(q^1) = 0 // * q^2

q^1*(3*q^0-2/5*q^2-4*q^1) = 0

q^1

(-2/5)*q^2-4*q+3 = 0

(-2/5)*q^2-4*q+3 = 0

DELTA = (-4)^2-(3*4*(-2/5))

DELTA = 104/5

DELTA > 0

q = ((104/5)^(1/2)+4)/(2*(-2/5)) or q = (4-(104/5)^(1/2))/(2*(-2/5))

q = -5/4*((104/5)^(1/2)+4) or q = -5/4*(4-(104/5)^(1/2))

q in { -5/4*((104/5)^(1/2)+4), -5/4*(4-(104/5)^(1/2))}

q in { -5/4*((104/5)^(1/2)+4), -5/4*(4-(104/5)^(1/2)) }

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