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3/w+5=1/2w
We move all terms to the left:
3/w+5-(1/2w)=0
Domain of the equation: w!=0
w∈R
Domain of the equation: 2w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
3/w-(+1/2w)+5=0
We get rid of parentheses
3/w-1/2w+5=0
We calculate fractions
6w/2w^2+(-w)/2w^2+5=0
We add all the numbers together, and all the variables
6w/2w^2+(-1w)/2w^2+5=0
We multiply all the terms by the denominator
6w+(-1w)+5*2w^2=0
Wy multiply elements
10w^2+6w+(-1w)=0
We get rid of parentheses
10w^2+6w-1w=0
We add all the numbers together, and all the variables
10w^2+5w=0
a = 10; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·10·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*10}=\frac{-10}{20} =-1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*10}=\frac{0}{20} =0 $
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