3/w-5+2/(w-5)(w+5)=1/w+5

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Solution for 3/w-5+2/(w-5)(w+5)=1/w+5 equation:



3/w-5+2/(w-5)(w+5)=1/w+5
We move all terms to the left:
3/w-5+2/(w-5)(w+5)-(1/w+5)=0
Domain of the equation: w!=0
w∈R
Domain of the equation: (w-5)(w+5)!=0
We move all terms containing w to the left, all other terms to the right
w-5)(w!=-5
w∈R
Domain of the equation: w+5)!=0
w∈R
We use the square of the difference formula
w^2+3/w-(1/w+5)-25-5=0
We get rid of parentheses
w^2+3/w-1/w-5-25-5=0
We multiply all the terms by the denominator
w^2*w-5*w-25*w-5*w+3-1=0
We add all the numbers together, and all the variables
w^2*w-35w+2=0
Wy multiply elements
w^3-35w+2=0
We do not support ewpression: w^3

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