3/x+1=9/4x+5

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Solution for 3/x+1=9/4x+5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+1 = (9/4)*x+5 // - (9/4)*x+5

3/x-((9/4)*x)-5+1 = 0

(-9/4)*x+3/x-5+1 = 0

3*x^-1-9/4*x^1-4*x^0 = 0

(3*x^0-9/4*x^2-4*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-9/4*x^2-4*x^1) = 0

x^1

(-9/4)*x^2-4*x+3 = 0

(-9/4)*x^2-4*x+3 = 0

DELTA = (-4)^2-(3*4*(-9/4))

DELTA = 43

DELTA > 0

x = (43^(1/2)+4)/(2*(-9/4)) or x = (4-43^(1/2))/(2*(-9/4))

x = -2/9*(43^(1/2)+4) or x = -2/9*(4-43^(1/2))

x in { -2/9*(43^(1/2)+4), -2/9*(4-43^(1/2))}

x in { -2/9*(43^(1/2)+4), -2/9*(4-43^(1/2)) }

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