3/x+2-4/2x-5=0

Solution for 3/x+2-4/2x-5=0 equation:

3/x+2-4/2x-5=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

3/x-4/2x-3=0

We calculate fractions


6x/2x^2+(-4x)/2x^2-3=0

We multiply all the terms by the denominator


6x+(-4x)-3*2x^2=0

Wy multiply elements

-6x^2+6x+(-4x)=0

We get rid of parentheses

-6x^2+6x-4x=0

We add all the numbers together, and all the variables

-6x^2+2x=0

a = -6; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-6}=\frac{-4}{-12}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-6}=\frac{0}{-12}
=0
$