3/x+2=(5/4x+8)+2

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Solution for 3/x+2=(5/4x+8)+2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+2 = (5/4)*x+2+8 // - (5/4)*x+2+8

3/x-((5/4)*x)-8-2+2 = 0

(-5/4)*x+3/x-8-2+2 = 0

3*x^-1-5/4*x^1-8*x^0 = 0

(3*x^0-5/4*x^2-8*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-5/4*x^2-8*x^1) = 0

x^1

(-5/4)*x^2-8*x+3 = 0

(-5/4)*x^2-8*x+3 = 0

DELTA = (-8)^2-(3*4*(-5/4))

DELTA = 79

DELTA > 0

x = (79^(1/2)+8)/(2*(-5/4)) or x = (8-79^(1/2))/(2*(-5/4))

x = -2/5*(79^(1/2)+8) or x = -2/5*(8-79^(1/2))

x in { -2/5*(79^(1/2)+8), -2/5*(8-79^(1/2))}

x in { -2/5*(79^(1/2)+8), -2/5*(8-79^(1/2)) }

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