3/x+2=4/7-2x

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Solution for 3/x+2=4/7-2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+2 = 4/7-(2*x) // - 4/7-(2*x)

2*x+3/x-(4/7)+2 = 0

2*x+3/x-4/7+2 = 0

2*x^1+3*x^-1+10/7*x^0 = 0

(2*x^2+10/7*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+10/7*x^1+3*x^0) = 0

x^1

2*x^2+(10/7)*x+3 = 0

2*x^2+(10/7)*x+3 = 0

DELTA = (10/7)^2-(2*3*4)

DELTA = -1076/49

DELTA < 0

x in { } 

x belongs to the empty set

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