3/x+2=7/5x-1

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Solution for 3/x+2=7/5x-1 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+2 = (7/5)*x-1 // - (7/5)*x-1

3/x-((7/5)*x)+1+2 = 0

(-7/5)*x+3/x+1+2 = 0

3*x^-1-7/5*x^1+3*x^0 = 0

(3*x^1-7/5*x^2+3*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^1-7/5*x^2+3*x^0) = 0

x^1

(-7/5)*x^2+3*x+3 = 0

(-7/5)*x^2+3*x+3 = 0

DELTA = 3^2-(3*4*(-7/5))

DELTA = 129/5

DELTA > 0

x = ((129/5)^(1/2)-3)/(2*(-7/5)) or x = (-(129/5)^(1/2)-3)/(2*(-7/5))

x = -5/14*((129/5)^(1/2)-3) or x = 5/14*((129/5)^(1/2)+3)

x in { -5/14*((129/5)^(1/2)-3), 5/14*((129/5)^(1/2)+3)}

x in { -5/14*((129/5)^(1/2)-3), 5/14*((129/5)^(1/2)+3) }

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