3/x+4=2/3x-4

Solution for 3/x+4=2/3x-4 equation:

3/x+4=2/3x-4

We move all terms to the left:

3/x+4-(2/3x-4)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 3x-4)!=0

x∈R


We get rid of parentheses

3/x-2/3x+4+4=0

We calculate fractions


9x/3x^2+(-2x)/3x^2+4+4=0

We add all the numbers together, and all the variables

9x/3x^2+(-2x)/3x^2+8=0

We multiply all the terms by the denominator


9x+(-2x)+8*3x^2=0

Wy multiply elements

24x^2+9x+(-2x)=0

We get rid of parentheses

24x^2+9x-2x=0

We add all the numbers together, and all the variables

24x^2+7x=0

a = 24; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·24·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*24}=\frac{-14}{48}
=-7/24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*24}=\frac{0}{48}
=0
$