3/x+4=7/2x+17/4

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Solution for 3/x+4=7/2x+17/4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+4 = (7/2)*x+17/4 // - (7/2)*x+17/4

3/x-((7/2)*x)-(17/4)+4 = 0

(-7/2)*x+3/x-17/4+4 = 0

3*x^-1-7/2*x^1-1/4*x^0 = 0

(3*x^0-7/2*x^2-1/4*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-7/2*x^2-1/4*x^1) = 0

x^1

(-7/2)*x^2+(-1/4)*x+3 = 0

(-7/2)*x^2+(-1/4)*x+3 = 0

DELTA = (-1/4)^2-(3*4*(-7/2))

DELTA = 673/16

DELTA > 0

x = ((673/16)^(1/2)-(-1/4))/(2*(-7/2)) or x = (-(-1/4)-(673/16)^(1/2))/(2*(-7/2))

x = ((673/16)^(1/2)+1/4)/(-7) or x = (1/4-(673/16)^(1/2))/(-7)

x in { ((673/16)^(1/2)+1/4)/(-7), (1/4-(673/16)^(1/2))/(-7)} 

x in { ((673/16)^(1/2)+1/4)/(-7), (1/4-(673/16)^(1/2))/(-7) }

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