3/x+7+17/2x=1/x

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Solution for 3/x+7+17/2x=1/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(17/2)*x+3/x+7 = 1/x // - 1/x

(17/2)*x+3/x-(1/x)+7 = 0

(17/2)*x+3/x-x^-1+7 = 0

17/2*x^1+2*x^-1+7*x^0 = 0

(17/2*x^2+7*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(17/2*x^2+7*x^1+2*x^0) = 0

x^1

(17/2)*x^2+7*x+2 = 0

(17/2)*x^2+7*x+2 = 0

DELTA = 7^2-(2*4*(17/2))

DELTA = -19

DELTA < 0

x in { } 

x belongs to the empty set

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