3/x+7x=x/7

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Solution for 3/x+7x=x/7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7*x+3/x = x/7 // - x/7

7*x-(x/7)+3/x = 0

48/7*x^1+3*x^-1 = 0

(48/7*x^2+3*x^0)/(x^1) = 0 // * x^2

x^1*(48/7*x^2+3*x^0) = 0

x^1

(48/7)*x^2+3 = 0

(48/7)*x^2+3 = 0

DELTA = 0^2-(3*4*(48/7))

DELTA = -576/7

DELTA < 0

x in { } 

x belongs to the empty set

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