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3/x+8/4x=5
We move all terms to the left:
3/x+8/4x-(5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x!=0We calculate fractions
x!=0/4
x!=0
x∈R
12x/4x^2+8x/4x^2-5=0
We multiply all the terms by the denominator
12x+8x-5*4x^2=0
We add all the numbers together, and all the variables
20x-5*4x^2=0
Wy multiply elements
-20x^2+20x=0
a = -20; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-20)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-20}=\frac{-40}{-40} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-20}=\frac{0}{-40} =0 $
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