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3/x-1/2x-1=2
We move all terms to the left:
3/x-1/2x-1-(2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3/x-1/2x-3=0
We calculate fractions
6x/2x^2+(-x)/2x^2-3=0
We add all the numbers together, and all the variables
6x/2x^2+(-1x)/2x^2-3=0
We multiply all the terms by the denominator
6x+(-1x)-3*2x^2=0
Wy multiply elements
-6x^2+6x+(-1x)=0
We get rid of parentheses
-6x^2+6x-1x=0
We add all the numbers together, and all the variables
-6x^2+5x=0
a = -6; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-6)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-6}=\frac{-10}{-12} =5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-6}=\frac{0}{-12} =0 $
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