3/x-12=x-4

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Solution for 3/x-12=x-4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x-12 = x-4 // - x-4

3/x-x-12+4 = 0

3*x^-1-1*x^1-8*x^0 = 0

(3*x^0-1*x^2-8*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-1*x^2-8*x^1) = 0

x^1

3-x^2-8*x = 0

3-x^2-8*x = 0

DELTA = (-8)^2-(-1*3*4)

DELTA = 76

DELTA > 0

x = (76^(1/2)+8)/(-1*2) or x = (8-76^(1/2))/(-1*2)

x = (2*19^(1/2)+8)/(-2) or x = (8-2*19^(1/2))/(-2)

x in { (2*19^(1/2)+8)/(-2), (8-2*19^(1/2))/(-2)} 

x in { (2*19^(1/2)+8)/(-2), (8-2*19^(1/2))/(-2) }

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