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3/x-2=12/2x-1
We move all terms to the left:
3/x-2-(12/2x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-1)!=0We get rid of parentheses
x∈R
3/x-12/2x+1-2=0
We calculate fractions
6x/2x^2+(-12x)/2x^2+1-2=0
We add all the numbers together, and all the variables
6x/2x^2+(-12x)/2x^2-1=0
We multiply all the terms by the denominator
6x+(-12x)-1*2x^2=0
Wy multiply elements
-2x^2+6x+(-12x)=0
We get rid of parentheses
-2x^2+6x-12x=0
We add all the numbers together, and all the variables
-2x^2-6x=0
a = -2; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-2)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-2}=\frac{0}{-4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-2}=\frac{12}{-4} =-3 $
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