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3/x-2=2x-1/x+2
We move all terms to the left:
3/x-2-(2x-1/x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
3/x-2x+1/x-2-2=0
We multiply all the terms by the denominator
-2x*x-2*x-2*x+3+1=0
We add all the numbers together, and all the variables
-4x-2x*x+4=0
Wy multiply elements
-2x^2-4x+4=0
a = -2; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·(-2)·4
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{3}}{2*-2}=\frac{4-4\sqrt{3}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{3}}{2*-2}=\frac{4+4\sqrt{3}}{-4} $
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