3/x-5=-4/x+3/(x-5)(x+3)

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Solution for 3/x-5=-4/x+3/(x-5)(x+3) equation:


D( x )

x-5 = 0

x = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x = 0

x = 0

x in (-oo:0) U (0:5) U (5:+oo)

3/x-5 = (3/(x-5))*(x+3)-4/x // - (3/(x-5))*(x+3)-4/x

3/x-((3/(x-5))*(x+3))-(-4/x)-5 = 0

3/x-3*(x+3)*(x-5)^-1+4*x^-1-5 = 0

(-3*(x+3))/(x-5)+3/x+4/x-5 = 0

(-3*x*(x+3))/(x*(x-5))+(3*(x-5))/(x*(x-5))+(4*(x-5))/(x*(x-5))+(-5*x*(x-5))/(x*(x-5)) = 0

3*(x-5)-3*x*(x+3)+4*(x-5)-5*x*(x-5) = 0

4*x-3*x^2-5*x^2-6*x+25*x-20-15 = 0

25*x-3*x^2-5*x^2-2*x-35 = 0

23*x-8*x^2-35 = 0

23*x-8*x^2-35 = 0

23*x-8*x^2-35 = 0

DELTA = 23^2-(-35*(-8)*4)

DELTA = -591

DELTA < 0

1 = 0

1/(x*(x-5)) = 0

1/(x*(x-5)) = 0 // * x*(x-5)

1 = 0

x belongs to the empty set

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