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3/x-6+3/5x-30=11
We move all terms to the left:
3/x-6+3/5x-30-(11)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/x+3/5x-47=0
We calculate fractions
15x/5x^2+3x/5x^2-47=0
We multiply all the terms by the denominator
15x+3x-47*5x^2=0
We add all the numbers together, and all the variables
18x-47*5x^2=0
Wy multiply elements
-235x^2+18x=0
a = -235; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-235)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-235}=\frac{-36}{-470} =18/235 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-235}=\frac{0}{-470} =0 $
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