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3/x1=4/x+4
We move all terms to the left:
3/x1-(4/x+4)=0
Domain of the equation: x1!=0
x^1!=0/
x^1!=√0
x!=0
x∈R
Domain of the equation: x+4)!=0We get rid of parentheses
x∈R
3/x1-4/x-4=0
We calculate fractions
3x/x^2+(-4x)/x^2-4=0
We multiply all the terms by the denominator
3x+(-4x)-4*x^2=0
We add all the numbers together, and all the variables
-4x^2+3x+(-4x)=0
We get rid of parentheses
-4x^2+3x-4x=0
We add all the numbers together, and all the variables
-4x^2-1x=0
a = -4; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-4}=\frac{0}{-8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-4}=\frac{2}{-8} =-1/4 $
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