3/x=18/2x+4

Solution for 3/x=18/2x+4 equation:

3/x=18/2x+4

We move all terms to the left:

3/x-(18/2x+4)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x+4)!=0

x∈R


We get rid of parentheses

3/x-18/2x-4=0

We calculate fractions


6x/2x^2+(-18x)/2x^2-4=0

We multiply all the terms by the denominator


6x+(-18x)-4*2x^2=0

Wy multiply elements

-8x^2+6x+(-18x)=0

We get rid of parentheses

-8x^2+6x-18x=0

We add all the numbers together, and all the variables

-8x^2-12x=0

a = -8; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-8)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-8}=\frac{24}{-16}
=-1+1/2
$